# How do you calculate f''(1) and f'''(1) given #f(x)= 3- 6(x-1) + 4/(2!) (x-1)^2 - 5/(3!) (x-1)^3 + 1/(4!) (x-1)^4#?

##### 1 Answer

Dec 31, 2016

The Taylor series for

#### Explanation:

So the Taylor series for

Comparing the given function with the general expression for the Taylor series for

So

**If you prefer** , you could differentiate to get

So