How do you calculate #lim x->3# of #(x^2-2x-3)/(x-3)#?
1 Answer
Dec 12, 2016
By factoring.
#color(blue)(lim_(x->3) (x^2 - 2x - 3)/(x - 3))#
#= lim_(x->3) (cancel((x - 3))(x + 1))/cancel(x - 3)#
#= color(blue)(4)#
