Question

How do you calculate `log_(1/2) 4`?

Answer 1

`-2`

Explanation:

For long-term-memory: #log_b a=.log_c a/log_c b=log a/log b=ln a/

Here, `log_(1/2) 4`

`= log 4/log (1/2)`

`=log 2^2/(-log 2)`
`=-2 log 2/log 2=-2` #