How do you calculate #log 1.485*10^6#?

1 Answer
Jan 21, 2017

Answer:

Using properties of logs, you can rewrite the problem as #log(1.485) + log(10^6)#.

Explanation:

This will simplify to #log(1.485) + 6#.
A calculator is required in order to figure out #log(1.485)# so, you would get: .1717 + 6 or 6.1717