# How do you calculate log 1.485*10^6?

Using properties of logs, you can rewrite the problem as $\log \left(1.485\right) + \log \left({10}^{6}\right)$.
This will simplify to $\log \left(1.485\right) + 6$.
A calculator is required in order to figure out $\log \left(1.485\right)$ so, you would get: .1717 + 6 or 6.1717