How do you calculate #log _24 356#?

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Answer 1 · 2016-06-22T09:14:50

1.849

Use the change of base law:

#log_24 356 = (log 356)/(log24)#

This is calculated on a calculator to give: 1.849

The same result can be obtained from using index form first:

Let #log_24 356 = x#

#24^x = 356#

#log24^x = log356#

#xlog24 = 356#

#x = (log356)/(log24) = 1.849#