How do you calculate Log_5 16log516?

1 Answer

color(maroon)(=> 1.72271.7227

Explanation:

log_5 16log516

log_b a = log_x a/ log _x blogba=logxalogxb, applying change of base rule.

Let b = 10b=10

=> log 16 / log 5log16log5

=> log 2^4 / log 5log24log5

=> (4 log 2 )/ log 5" "larr4log2log5 use a calculator or tables from here

=> color(maroon)(1.72271.7227