Question

How do you calculate `log_9(1/7)`?

Answer 1

`-loh 7/log 9=-0.8856`, nearly.

Explanation:

Use `log_b a^n=n log_b a and log_b a=log_c a/log_c b`

Here, `log_9(1/7)=log_9(7^(-1))=-log_9 7= - log 7/log 9`