Question

How do you calculate `log10^3 + log10(y^2)`?

Answer 1

`color(green)(4+log_10 y^2)`

Explanation:

Since the default base for `log` is `10`

`log 10^3=log_10 10^3 = 3`

and remembering that `log_b pq =log_b p +log_b q`
`log 10(y^2)=log_10 10 +log_10 (y^2)=1 +log_10 (y^2)`

Therefore
`log 10^3 + log 10(y^2) = 4 + log_10 (y^2)`