How do you calculate $log10^3 + log10(y^2)$ ?

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Answer 1 · 2016-09-20T18:12:15

$color(green)(4+log_10 y^2)$

Since the default base for $log$ is $10$

$log 10^3=log_10 10^3 = 3$

and remembering that $log_b pq =log_b p +log_b q$
$log 10(y^2)=log_10 10 +log_10 (y^2)=1 +log_10 (y^2)$

Therefore
$log 10^3 + log 10(y^2) = 4 + log_10 (y^2)$

How do you calculate log10^3 + log10(y^2)log10^3 + log10(y^2)?