# How do you calculate Molar Solubility in grams/100mL of Calcium iodate in water at 25 degrees Celsius? Ksp = #7.1 x 10^-7#

##### 1 Answer

#### Explanation:

We write out the dissolution reaction:

And then we write out the equilibrium expression, in which

If we dub the solubility of calcium iodate under these conditions as

This expression follows the equilibrium equation: each equiv of salt that dissolves gives 1 equiv of

Thus

This gives an answer in