# How do you calculate the antilog of 2?

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Alan P. Share
Jun 12, 2016

antilog(2)$= 100$

#### Explanation:

(Remember that the default base for $\log$ is $10$)

If $\log \left(a\right) = b$
then $\text{antilog} \left(b\right) = a$

We are asked for $a = \text{antilog} \left(2\right)$

So we are looking for the value $a$ for which
$\textcolor{w h i t e}{\text{XXX}} \log \left(a\right) = 2$

By definition of $\log$
$\textcolor{w h i t e}{\text{XXX}} \log \left(a\right) = 2$
means
$\textcolor{w h i t e}{\text{XXX}} {10}^{2} = a$

$\Rightarrow a = 100$

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