How do you calculate the antilog of 2?

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Alan P. Share
Jun 12, 2016

Answer:

antilog(2)#=100#

Explanation:

(Remember that the default base for #log# is #10#)

If #log(a)=b#
then #"antilog"(b)=a#

We are asked for #a="antilog"(2)#

So we are looking for the value #a# for which
#color(white)("XXX")log(a)=2#

By definition of #log#
#color(white)("XXX")log(a)=2#
means
#color(white)("XXX")10^2=a#

#rArr a=100#

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