How do you calculate the concentration of #H^+# ions in a 0.27 M NaoH solution?
1 Answer
Explanation:
We gots the equilibrium
For which
Now logarithms were used in the old days before electronic calculators given that they allow the multiplication of large or small numbers fairly easily..
But by definition of the logarithmic function,
And we got
And
And finally, we take antilogarithms...