# How do you calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs #6.75 * 10^4# joules of heat, and its temperature changes from 32°C to 57°C?

##### 1 Answer

#### Answer:

#### Explanation:

A substance's **specific heat** tells you how much heat much either be *added* or *removed* from **change in temperature**.

The equation that establishes a relationship between specific heat, heat added or removed, and change in temperature looks like this

#color(blue)(q = m * c * DeltaT)" "# , where

*change in temperature*

In your case, the **absorb** a total of *increase* from

The difference between the final temperature and the initial temperature of the sample will be the value for

#DeltaT = 57^@"C" - 32^@"C" = 25^@"C"#

This means that the specific heat of the wood is equal to

#q = m * c * DeltaT implies c = q/(m * DeltaT)#

Plug in your values to get

#c = (6.75 * 10^4"J")/("1500.0 g" * 25^@"C") = color(green)(1.8"J"/("g" ""^@"C"))#

The answer is rounded to two sig figs, the number of sig figs you have for the two temperatures of the sample.