How do you calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs #6.75 * 10^4# joules of heat, and its temperature changes from 32°C to 57°C?
A substance's specific heat tells you how much heat much either be added or removed from
The equation that establishes a relationship between specific heat, heat added or removed, and change in temperature looks like this
#color(blue)(q = m * c * DeltaT)" "#, where
In your case, the
The difference between the final temperature and the initial temperature of the sample will be the value for
#DeltaT = 57^@"C" - 32^@"C" = 25^@"C"#
This means that the specific heat of the wood is equal to
#q = m * c * DeltaT implies c = q/(m * DeltaT)#
Plug in your values to get
#c = (6.75 * 10^4"J")/("1500.0 g" * 25^@"C") = color(green)(1.8"J"/("g" ""^@"C"))#
The answer is rounded to two sig figs, the number of sig figs you have for the two temperatures of the sample.