How do you calculate the number of atoms in 7.50 mol of S?

Mulitiply $7.5 \cdot m o l$ by $\text{Avogadro's number...........}$
And $\text{Avogadro's number}$, $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$ specifies a molar quantity......
And so $7.5 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 \cong 4.5 \times {10}^{24}$ $\text{sulfur atoms}$. What is the mass of this quantity of sulfur atoms?