# How do you calculate the number of grams in 1.023 moles?

$1.023 \cdot \text{moles}$ specifies $1.023 \times {N}_{A}$ individual items of stuff where ${N}_{A} = \text{Avogadro's Number} = 6.022 \times {10}^{23} m o {l}^{-} 1$. ${N}_{A}$ has the property that ${N}_{A} \times \text{^1H" atoms}$ has a mass of $1 \cdot g$ precisely!