How do you calculate the number of grams of solute in 250.0 mL of 0.179 M KOH?

1 Answer
anor277
Jul 14, 2017

We use the formula....."Concentration"="Moles of solute"/"Volume of solution", and get approx. 2.5*g KOH.

Explanation:

And so (i) we calculate the molar quantity.....

"Moles of KOH"="concentration"xx"volume"=0.179*mol*L^-1xx250.0*mLxx10^-3*L*mL^-1=4.475xx10^-2*mol.

And then (ii) we multiply this molar quantity by the formula mass of KOH, .....4.475xx10^-2*molxx56.11*g*mol^-1=??*g

Can you tell us pOH and pH of this solution...........?

Related questions
See all questions in Solutions
Impact of this question
14202 views around the world
You can reuse this answer
Creative Commons License