How do you calculate the number of grams of solute in 250.0 mL of 0.179 M KOH?

1 Answer
anor277
Jul 14, 2017

We use the formula.....#"Concentration"="Moles of solute"/"Volume of solution"#, and get approx. #2.5*g# #KOH#.

Explanation:

And so (i) we calculate the molar quantity.....

#"Moles of KOH"="concentration"xx"volume"=0.179*mol*L^-1xx250.0*mLxx10^-3*L*mL^-1=4.475xx10^-2*mol.#

And then (ii) we multiply this molar quantity by the formula mass of #KOH#, .....#4.475xx10^-2*molxx56.11*g*mol^-1=??*g#

Can you tell us #pOH# and #pH# of this solution...........?

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