How do you calculate the number of molecules in 4.00 moles H_2S?

Multiply $4 \cdot m o l$ by $\text{Avogadro's number.....}$
Here we use $\text{Avogadro's number}$ as we would any other collective number, a dozen, a gross, a 100, or 1000........except that $\text{Avogadro's number}$ is unfeasibly large......and specifies $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.
And thus for ${H}_{2} S$ we have $4 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$ $=$ $24 \times {10}^{23}$ molecules. Can you tell me how many sulfur, and how many hydrogen atoms you got in this molar quantity? I think you could be able to do so.