# How do you calculate the number of moles of solute in 98.97 mL of 0.1585 M K_2Cr_2O_7 (aq)?

Dec 24, 2017

Simply take the product...$\text{volume"xx"concentration}$ to give an answer in $\text{moles}$.

#### Explanation:

By definition, $\text{Concentration"="Moles of solute"/"Volume of solution}$.

And thus ${n}_{\text{moles of solute"="concentration"xx"volume}}$

=0.1585*mol*L^-1xx98.97*mLxx10^-3*L*mL^-1=??*mol

Note the dimensional consistency of the product. We wanted an answer in moles, and the product gave us one....i.e.

$0.1585 \cdot m o l \cdot \cancel{{L}^{-} 1} \times 98.97 \cdot \cancel{m L} \times {10}^{-} 3 \cdot \cancel{L \cdot m {L}^{-} 1} .$

=??mol