# How do you calculate the number of oxygen atoms in 9.20 moles of magnesium iodate?

$3.25 \cdot {10}^{25}$ atoms $O$
$9.20 \cdot m o l \cdot M g {\left(I {O}_{3}\right)}_{2} \cdot$ $\frac{6 \cdot m o l \cdot O}{1 \cdot m o l \cdot M g {\left(I {O}_{3}\right)}_{2}} \cdot$$\frac{6.02 \cdot {10}^{23} \cdot O}{1 \cdot m o l \cdot O}$
$= 3.25 \cdot {10}^{25}$ atoms $O$