Question

How do you calculate the percent composition of chromium in `BaCrO_4`?

Answer 1

In barium chromate....?

Explanation:

Well, we divide the molar mass of EACH element by the molar mass of the salt...

`%Ba-=(137.31*g)/(253.37* g*mol^-1 )xx100%=54.2%`

`%Cr-=(52.00*g)/(253.37* g*mol^-1 )xx100%=20.5%`

`%O-=(64.00*g)/(253.37* g*mol^-1 )xx100%=25.3%`

Do the elemental percentage sum to `100%`? Should they do so?