How do you calculate the percent composition of chromium in #BaCrO_4#?

1 Answer
Aug 1, 2018

Answer:

In barium chromate....?

Explanation:

Well, we divide the molar mass of EACH element by the molar mass of the salt...

#%Ba-=(137.31*g)/(253.37* g*mol^-1 )xx100%=54.2%#

#%Cr-=(52.00*g)/(253.37* g*mol^-1 )xx100%=20.5%#

#%O-=(64.00*g)/(253.37* g*mol^-1 )xx100%=25.3%#

Do the elemental percentage sum to #100%#? Should they do so?