# How do you calculate the percentage composition of Iodine in NI_3?

Mar 1, 2016

$N {I}_{3}$ has over 96% iodine content by mass.
The molecular mass of $N {I}_{3}$ is $394.72$ $g \cdot m o {l}^{-} 1$.
Thus, %I $=$ "Mass of iodine"/"Mass of nitrogen triiodide"xx100% $=$ (3xx126.9*g*mol^-1)/(394.72*g*mol^-1)xx100% $=$ ??%