Question

How do you calculate the percentage composition of Oxygen in `N_2O_5`?

Answer 1

`25.93%` `N`, `74.07%` `O`

Explanation:

You first need refrence a periodic table to find the weight of `N` and `O`

`N` = `14.0g`
`O` = `16.0g`

Multiply each element based on how many of each element are in the compound. for `N`, it is 2. For `O`, it is 5.

`14.0g` `O` * 2 = `28.0g` `N`

`16.0g` `O` * 5 = `80.0g` `O`

add the two weights together to get the total weight of `N_2O_5`

`28.0g` + `80.0g` = `108g` `N_2O_5`

Divide each elements weight by the total weight of the compound and multiply by 100 and you will have the percentage composition

`(28.0gN)/(108g)` * 100 = `25.93%` `N`

`(80.0gO)/(108g)` * 100 = `74.07%` `O`