How do you combine #(4n ^ { 4} - 1- 4n ^ { 2} ) - ( 2n ^ { 2} + 2n ^ { 4} + 3)#?

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Answer 1 · 2018-01-27T13:53:43

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#4n^4 - 1 - 4n^2 - 2n^2 - 2n^4 - 3#

Next, group like terms:

#4n^4 - 2n^4 - 4n^2 - 2n^2 - 1 - 3#

Now, combine like terms:

#(4 - 2)n^4 + (-4 - 2)n^2 + (-1 - 3)#

#2n^4 + (-6)n^2 + (-4)#

#2n^4 - 6n^2 - 4#