How do you combine #7/(4xy^2) + 5/(8x^2y)#?

1 Answer
Apr 14, 2017

See the entire solution process below:

Explanation:

To add the two fractions we must put both fractions over a common denominator. In this problem as common denominator is: #8x^2y^2#. The first step then is to multiple each fraction by the appropriate form of #1# to obtain this common denominator.

#7/(4xy^2) + 5/(8x^2y) = ((2x)/(2x) * 7/(4xy^2)) + (y/y * 5/(8x^2y)) = #

#(14x)/(8x^2y^2) + (5y)/(8x^2y^2)#

we can now add the numerators over the common denominator:

#(14x)/(8x^2y^2) + (5y)/(8x^2y^2) = (14x + y)/(8x^2y^2)#