Question

How do you combine like terms in `2n ^ { 3} ( 4n ^ { 4} - 5n ^ { 2} - 6) - 4n ^ { 3} ( 6n ^ { 2} + n ^ { 4} - 7)`?

Answer 1

`2n^3*(n^2-8)*(2n^2-1)`

Explanation:

`2n^3*(4n^4-5n^2-6-2(6n^2+n^4-7)`

`2n^3*(4n^4-5n^2-6-12n^2-2n^4+14)`

`2n^3*(2n^4-17n^2+8)`

`2n^3*(n^2*(2n^2-1)-8(2n^2-1))`