How do you solve the system of equations #y= 3x + 12# and #2x - 2y = - 4#? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer xPrrox · Stefan V. Jun 20, 2018 Substitution. Explanation: #y=3x+12 " " " "(1)# #2x-2y =-4# #-2y=-4-2x# So #y=(-4-2x)/-2# #y= 2+x" " " "(2)# Sub #(2)# into #(1)# #3x+ 12= 2 +x# #2x=-10# #x=-5# Sub #x=-5# into #(1)# (I would normally sub it into a given equation as I may have done a mistake in my new equation) #y= 3(-5)+12# #y=-3# Therefore, #y= -3 and x= -5# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 423 views around the world You can reuse this answer Creative Commons License