How do you complete the equation #C_8H_18 -> C_6H_14 + __#?

2 Answers
Apr 12, 2018

Answer:

#"C"_2"H"_4#

Explanation:

#"C"_8"H"_18 -> "C"_6"H"_14 + "__" #

There are #8# carbons & #18# Hydrogens in reactant side and #6# carbons & #14# Hydrogens in product side. So, another molecule should contain #2# carbons and #4# Hydrogens.

#"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)#
#color(white)(............................)"ethene"#

Apr 12, 2018

it is the example of Aromatization in which higher alkanes is divided into smaller akanes & alkenes.
so, eqn is,
#C_8H_18 rarr C_6H_14 + C_2H_4#
octane #rarr# hexane + ethene