How do you complete the square 3x^2-6x-1=0? Precalculus Linear and Quadratic Functions Completing the Square 1 Answer Massimiliano Feb 4, 2015 The answer is: 3(x^2-2x)-1=0rArr3(x^2-2x+1-1)-1=0rArr 3(x^2-2x+1)-3-1=0rArr3(x-1)^2-4=0rArr (x-1)^2=4/3rArrx-1=+-sqrt(4/3)=0rArr x=1+-2/sqrt3rArrx=1+-(2sqrt3)/3rArr x=(3+-2sqrt3)/3. Answer link Related questions What does completing the square mean? How do I complete the square? Does completing the square always work? Is completing the square always the best method? Do I need to complete the square if f(x) = x^2 - 6x + 9? How do I complete the square if f(x) = x^2 + 4x - 9? How do I complete the square if the coefficient of x^2 is not 1? How do I complete the square if f(x) = 3x^2 + 12x - 9? If I know the quadratic formula, why must I also know how to complete the square? How do I use completing the square to describe the graph of f(x)=30-12x-x^2? See all questions in Completing the Square Impact of this question 2934 views around the world You can reuse this answer Creative Commons License