Question

How do you complete the square `3x^2-6x-1=0`?

Answer 1

The answer is:

`3(x^2-2x)-1=0rArr3(x^2-2x+1-1)-1=0rArr`

`3(x^2-2x+1)-3-1=0rArr3(x-1)^2-4=0rArr`

`(x-1)^2=4/3rArrx-1=+-sqrt(4/3)=0rArr`

`x=1+-2/sqrt3rArrx=1+-(2sqrt3)/3rArr`

`x=(3+-2sqrt3)/3`.