How do you completely factor #5y^3-5y^2-10y#?

1 Answer
sjc
Oct 9, 2017

#5y^3-5y-10y=5y(y-2)(y+1)#

Explanation:

start by taking out any common factors

#5y^3-5y-10y=5y(y^2-y-2)#

we now factorise the bracket as a quadratic

we need the factors of #-2# that sum to #-1#

ie#-2, +1#

#5y^3-5y-10y=5y(y-2)(y+1)#

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