How do you completely factor #a^(6b) + a^(2b+5)#?
1 Answer
Jan 19, 2016
#a^(6b)+a^(2b+5)=a^(2b)(a^(4b)+a^5)#
Explanation:
Note that in general
Hence:
#a^(6b)+a^(2b+5)#
#=a^(2b)a^(4b)+a^(2b)a^5#
#=a^(2b)(a^(4b)+a^5)#
