# How do you compute the value of int x^3 dx of [0,3]?

$\frac{81}{4}$
${\int}_{0}^{3} {x}^{3} \mathrm{dx} = {x}^{4} / 4 {|}^{3 , 0}$
$= {3}^{4} / 4 - 0$
$= \frac{81}{4}$