How do you condense $\frac{1}{2} ln 9 + ln 3 x$ $1/2 ln 9 + ln 3 x$ ?

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How do you condense $\frac{1}{2} ln 9 + ln 3 x$ $1/2 ln 9 + ln 3 x$ ?

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Answer 1 · 2016-05-29T06:47:40

It is

$\frac{1}{2} ln 9 + ln 3 x = {ln 9}^{\frac{1}{2}} + ln 3 x = ln \sqrt{9} + ln 3 x = ln 3 + ln 3 x = ln 9 x$ $1/2ln9+ln3x=ln9^(1/2)+ln3x=lnsqrt9+ln3x=ln3+ln3x=ln9x$

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How do you condense $\frac{1}{2} ln 9 + ln 3 x$ $1/2 ln 9 + ln 3 x$ ?

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