How do you condense #1/4log_3a+5log_3blog_3c#?
1 Answer
Mar 9, 2017
see below
Explanation:
Use the following Properties of Logarithim:

#log_b x^n =n log_b x# 
#log_b (xy)=log_bx+log_by# 
#log_b(x/y)=log_bxlog_by#
Hence,