How do you condense $2/3log_7(z-2)$ ?

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Answer 1 · 2018-03-16T10:40:52

$log_7(z-2)^(2/3)$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)log_b x^nhArrnlog_b x$

$rArr2/3log_7(z-2)=log_7(z-2)^(2/3)$

How do you condense 2/3log_7(z-2)2/3log_7(z-2)?