Question

How do you condense `2 log 6 + log(1/3)`?

Answer 1

`2log6+log(1/3)` `=log 12`

Explanation:

`2log6+log(1/3)`
`=log6^2+log(1/3)`-> use property `log_b x^n =nlog_bx`
`=log36+log(1/3)`
`=log(36*1/3)`-> use property `log_b x+log_b y = log_b (xy)`
`=log 12`