How do you condense $2 log (x + 2)$ $2 log(x+2)$ ?

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How do you condense $2 log (x + 2)$ $2 log(x+2)$ ?

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Answer 1 · 2016-03-22T17:36:45

$2 log (x + 2)$ $2log(x+2)$ $= log (x^{2} + 4 x + 4)$ $=log (x^2+4x+4)$

Explanation:

$2 log (x + 2)$ $2log(x+2)$
${log (x + 2)}^{2}$ $log(x+2)^2$ -> use property ${log}_{b} x^{n} = n \cdot {log}_{b} x$ $log_bx^n=n*log_bx$
$log (x^{2} + 4 x + 4)$ $log (x^2+4x+4)$ -> FOIL

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How do you condense $2 log (x + 2)$ $2 log(x+2)$ ?

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How do you condense $2 log (x + 2)$ $2 log(x+2)$ ?