How do you condense $2ln (2x+4) - Ln x - Ln 4 - Ln (x² + 4x + 4)$ ?

Question

1655 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-03T05:02:52

$- ln x$

Use $n ln m = ln (m^n) and ln (1/m) = - ln m.$ .

The expression = $ln (((2(x+2))^2)/((x)(4)(x+2)^2))$ .

Assume $x > 0)$ and cancel common factors.

Now, it reduces to $ln(1/x)=-ln x$

How do you condense 2ln (2x+4) - Ln x - Ln 4 - Ln (x² + 4x + 4)2ln (2x+4) - Ln x - Ln 4 - Ln (x² + 4x + 4)?