Question

How do you condense `2logx-log4-log3+logx`?

Answer 1

`log (x^3/12)`

Explanation:

If logs are added, the numbers are multiplied.
If logs are subtracted, the numbers are divided.

`2logx-log4-log3+logx`

=`logx^2 + logx -log4-log3`

=`log[(x^2 xx x)/(4xx3)]`

=`log (x^3/12)`