How do you condense #3 log_y3 + log_y 2 #?
1 Answer
Jun 3, 2016
Explanation:
Using the
#color(blue)"laws of logarithms"#
#•logx+logy=log(xy)...............(1)#
#•logx^nhArrnlogx................(2)# using (2) :
#3log_y3=log_y3^3=log_y27# using (1) :
#log_y27+log_y2=log_y(27xx2)=log_y54#
#rArr3log_y3+log_y2=log_y54#