How do you condense #3 log_y3 + log_y 2 #?

1 Answer
Jim G.
Jun 3, 2016

#log_y54#

Explanation:

Using the #color(blue)"laws of logarithms"#

#•logx+logy=log(xy)...............(1)#

#•logx^nhArrnlogx................(2)#

using (2) : #3log_y3=log_y3^3=log_y27#

using (1) : #log_y27+log_y2=log_y(27xx2)=log_y54#

#rArr3log_y3+log_y2=log_y54#

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