# How do you condense 3 logy3 + logy 2?

May 24, 2018

See below

#### Explanation:

I think you wanted to write $3 \log {y}^{3} + \log {y}^{2}$

In that case, by logarithm rules

3·3logy+2logy=9logy+2logy=11logy=logy^11

If you write, exactly that you want, then, by logarithm rules

$3 \log y + \log 3 + \log y + \log 2 = 4 \log y + \log 3 + \log 2$

The rules we have used are

logx·y=logx+logy
$\log {x}^{y} = y \log x$