# How do you condense 4ln2?

May 31, 2018

$\ln 16$

#### Explanation:

The key realization here is that we can use the logarithm property

$a \ln b = \ln \left({b}^{a}\right)$

Where the coefficient on $\ln$ becomes the exponent.

In our case, $a = 4$ and $b = 2$. We can rewrite $4 \ln 2$ as

$\ln \left({2}^{4}\right)$

which can be further simplified as

$\ln 16$

Hope this helps!