How do you condense 6log(x)-log(17) to a simple logarithm?

$\log \left({x}^{6} / 17\right)$
There are some laws of logarithms. One of them is the powers of logarithms. For instance, if we have the function $f \left(x\right) = {\log}_{a} \left({b}^{c}\right)$ , then we can rewrite this as $f \left(x\right) = c {\log}_{a} \left(b\right)$. Since we are trying to condense the expression into a single logarithm, $6 \log \left(x\right)$ is equal to $\log \left({x}^{6}\right)$. Another law of logarithms is if we have the expression ${\log}_{a} \left(b\right) - {\log}_{a} \left(c\right)$, we can rewrite this as ${\log}_{a} \left(\frac{b}{c}\right)$. So $\log \left({x}^{6}\right) - \log \left(17\right) = \log \left({x}^{6} / 17\right)$