How do you condense $ln x + ln 3$ $ln x + ln 3$ ?

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Answer 1 · 2016-05-05T23:00:48

I found $ln (3 x)$ $ln(3x)$

You can change it into the log of the product of the argments as:
$ln x + ln 3 = ln (3 x)$ $lnx+ln3=ln(3x)$

How do you condense ln x + ln 3lnx+ln3 ln x + ln 3?