How do you condense #ln z - 3 ln x#?

1 Answer
May 6, 2016

Answer:

I thought this:

Explanation:

We can start by writing the #3# as exponent of the argument of the second log:
#lnz-lnx^3=#
ad then we condense the subtraction as a division of arguments:
#=ln(z/x^3)#
This is the best I got!