How do you condense $ln x + ln 3$ $lnx+ln3$ ?

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Answer 1 · 2017-02-23T23:34:00

$ln 3 x$ $ln 3x$

Remember: ${log}_{a} b + {log}_{a} c = {log}_{a} (b \times c)$ $log_a b + log_a c = log_a (bxxc)$
and: $ln x = {log}_{e} x$ $ln x = log_e x$

Hence: $ln x + ln 3 = ln (x \times 3) = ln 3 x$ $ln x + ln 3 = ln(x xx 3) = ln 3x$

How do you condense lnx+ln3lnx+ln3?