How do you condense $log_2 4+ 3log_2 9$ ?

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Answer 1 · 2016-10-12T22:13:40

$log_2(4)+3log_2(9)=log_2(2916)~~11.5$

We will use the following properties of logarithms:

With those, we have

$log_2(4)+3log_2(9) = log_2(4)+log_2(9^3)$

$=log_2(4*9^3)$

$=log_2(2916)$

How do you condense log_2 4+ 3log_2 9log_2 4+ 3log_2 9?