How do you condense #log_2((8x^2)/y)+log_2(2xy)#?

1 Answer
Jul 19, 2016

Answer:

#log_2(16x^3)#

Explanation:

If two log terms are being added, then it means that the numbers are being multiplied. The two terms can be written as the log of a single number. The bases of the logs are the same.

#log_2((8x^2)/y)+log_2(2xy)#

=#log_2[(8x^2)/y xx 2xy]#

=#log_2(16x^3)#