# How do you condense #log_3 (9xy^2)-log_3 (27xy)#?

##### 1 Answer

Jul 9, 2016

#### Answer:

#### Explanation:

Using the

#color(blue)"law of logarithms"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(loga-logb=log(a/b))color(white)(a/a)|)))#

#rArrlog_3(9xy^2)-log_3(27xy)=log_3((9xy^2)/(27xy))# which then simplifies to

#log_3(y/3)#