How do you condense $log(3x + 7) - log x$ ?

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Answer 1 · 2016-03-22T19:10:06

$log(3x+7)-logx$ $=log((3x+7)/(x))$

$log(3x+7)-logx$
$=log((3x+7)/(x))$ -> use property $log_bx-log_by = log_b (x/y)$

How do you condense log(3x + 7) - log xlog(3x + 7) - log x?