How do you condense $log_4z-log_4y$ ?

Question

2210 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-07T13:46:07

$color(blue)(log_4(z/y)$

By the laws of logarithms:

$log_c(a/b)=log_c(a)-log_c(b)$

$:.$

$log_4z-log_4y=log_4(z/y)$

$color(blue)(log_4(z/y)$

Answer 2 · 2018-04-07T13:49:54

$log_4(z/y)$

$"using the "color(blue)"law of logarithms"$

$•color(white)(x)loga-logb=log(a/b)$

$rArrlog_4z-log_4y=log_4(z/y)$

How do you condense log_4z-log_4ylog_4z-log_4y?