How do you condense #log x + log (x^2 - 196) - log 2 - log (x - 14)#?

Question

1436 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-29T15:11:25

#log(x+14)#

#log(x^2-196)=log(x^2-14^2)=log((x-14)*(x+14))#
#log x+log((x-14)(x+14))-log 2-log(x-14)#

#log x+cancel(log (x-14)) + log(x+14)-log 2-cancel(log(x-14))#

#log x+log(x+14)-log x#

#log(x*(x+14))-log x#

#log(x^2+14x)-log x#

#log((x^2+14x)/x)#

#log(x+14)#